@JeetanKumarUpadhyayUpadhyay

Guys,We can solve it as follows:-
Taking the equation and squaring on bothe sides then 
(x⁹⁹+1/x⁹⁹)²=169 
Applying (a+b)²=(a-b)²+4ab we get
(x⁹⁹-1/x⁹⁹)²+4×x⁹⁹×1/x⁹⁹=169
(x⁹⁹-1/⁹⁹)²+4=169
By subtracting 4 from both sides we get
(x⁹⁹-1/x⁹⁹)²=165
By Rooting both sides we get
x⁹⁹-1/x⁹⁹=√165 
So his method is right and we get 4 from applying all the identity

@prabhavkumar3986

(a-b)^2 = (a+b)^2 - 4ab

@ajadbhai7398

Those who cant understand 

A+b whole squre is a2plus b2  plus 2ab thus substitute a2 plus b2 by a-b whole square thus we get to another 2ab add them you get 4ab and so on take a pen copy and solveit by yourselves you will get it

@Vikram.3708

Trick for this Q. Root n²-4

@nishantchauhan9166

Take x^99 as any other variable say y,apne aap solve kr luge

@taragoswami2664

√a²-4
a=13
√13²-4
√169-4
√165 answer

@Abhinab_Kalita

Lol.. ,consider x⁹⁹=a then (a+ 1/a)²=  169
a²+1/a²=169 -2

(a- 1/a)²=y²
169-2-2=y²
y=root under 165.........chilll

@crazyeducators7185

Sir -4 How will come.

@thegameoflife5722

Concept se krlo 2 min m ho jayenge trick ke piche mt bhago

@binaykumar6084

13 ka square 169- hai+me hoga 169+2=171

@jayantsaab2752

4 Kaha se Aaya pehle ye btao

@hindityping8982

Rule √n2-4

@Mathstricks4578

Sir 4 kaisa aaya

@LenMangte-b3b

For those who can't understand 
Go read your book instead of reading comment

@Son.Ali_24

Underroot 13^2-4

@priyadarshangarg1051

Those who don't know this problem could be done by Am greater or equal to Gm

@Akshaykumarmaths

Nice solution❤

@Anant_2030

Isme agar power different hogi tabhi yahi trick lagegi.pls reply

@ashutoshsingh7967

The correct ans for this problem is √11

@laggingsniper6165

Bhai logic to batao.. kis logic k basis pe steps kia?